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Question

Divide x29x10byx+1. Write down all steps involved in division.

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Solution


Divide x29x10byx+1
First,1 set up the divisionx+1x29x10For the moment,Ill ignore the other terms and look just at the leading x of the divisor and the leading x2 of the divided If I divide the leading x2 inside by the leading x inxx+1x29x10front, what would I get? Id get an x.SoIll put an x on top Now Ill take that x, and multiply it through thexx+1x29x10x2divisor,x+1.First,Imultiply then x(on top)by the x(on the "side"),and carry the x2 underneath: Then Ill multiply the x (on top) by the 1(on the "side")xx+1x29x10x2+1xand carry the 1x undermeath: Then Ill draw the "equals"bar,so I can do the subtractionxx+1x29x10x21x To subtract the polynomials,I change all the signs in the second line and then I add down.The first term (the x2)will cancel out:xx+1x29x10x21x10xI need to remember to carry down that last term,xx+1x29x10x21x10x10the "subtract ten",from the dividend: Now I look at the x from the divisor and the newx10x+qx29x10x21x10x10leading term,the10x,in the bottom line of the division If I divide the 10x by the x,I would end up with a10, so Ill put that on top: Now,Ill multiply the10(on top)by the leading xx10x+1x29x10x21x10x1010x(on the "side"),and carry the10x to the bottom and Ill multiply the 10(on top)by the 1 (on the "side"),x10x+1x29x10x21x10x1010x10and carry the10 to the bottom: I draw the equals bar,and change the signsx10x+1x29x10x21x10x10+10x+10the terms in the bottom row: Then I add down:x10x+1x29x10x21x10x10+10x+100
Then the solution to this division is : x-10

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