Divide x5-4 x3-x2-3 x-6 by x3-3 x-1- and then find the remainder and quotient-A- 7- x2-1B- 8- x2-1C- 7- x2-2D- 8- x2-2

The correct option is A 7, enclose [ x^2 1; x^3 3x+1 longdivx^5 4x^3+x^2+3x+6; x^5 3x^3+x^22; ...

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Division of a Polynomial by a Binomial

Divide x5-4 x...

Question

Divide $x^{5} - 4 x^{3} + x^{2} + 3 x + 6$ by $x^{3} - 3 x + 1$ ,and then find the remainder and quotient.

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Solution

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Similar questions

Divide polynomial $x^{4} + 4 x^{3} + 6 x^{2} + 4 x + 5$ by $x^{2} + 1$ and find the quotient.

x^{5} - 4 x^{3} + x^{2} + 3 x + 1

g (x)

(x^{2} - 1)

2

g (x)

The degree of the polynomial obtained when $8 - 6 x + x^{2} - 7 x^{3} + x^{5}$ is subtracted from $x^{4} - 6 x^{3} + x^{2} - 3 x + 1$ is:

\frac{- 13 x^{2} + 4 x^{3} + 2 x - 7}{x^{2} + 3 x - 2}

4 x^{3} + x^{2} + 5 x + 8

(x + 1)

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