Divide $(y^{3} - 3 y^{2} + 5 y - 1)$ by $(y - 1)$ to find quotient and remainder.

Open in App

Solution

$y^{2} - 2 y + 3$
_____
$y - 1) y^{3} - 3 y^{2} + 5 y - 1$
$y^{3} - y^{2}$

$- 2 y^{2} + 5 y - 1$
$- 2 y^{2} + 2 y$

$3 y - 1$
$3 y - 3$
_
$2$
Quotient $Q = y^{2} - 2 y + 3$ & Remainder $R = 2$ .

Suggest Corrections

Similar questions

(y^{3} - 3 y^{2} + 5 y - 1) \div (y - 1)

4 y^{3} - 3 y^{2} - 5 y + 1

2 y + 3

(2 m^{2} - 3 m + 10) \div (m - 5)

(x^{4} + 2 x^{3} + 3 x^{2} + 4 x + 5) \div (x + 2)

(y^{3} - 216) \div (y - 6)

(2 x^{4} + 3 x^{3} + 4 x - 2 x^{2}) \div (x + 3)

(x^{4} - 3 x^{2} - 8) \div (x + 4)

(y^{3} - 3 y^{2} + 5 y - 1) \div (y - 1)

x^{3} + 1

x + 1

y^{3} + y^{2} - 2 y + 1

(y - a) .

Join BYJU'S Learning Program