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Multiplication of Any Polynomial

Divide39 y ...

Question

Divide
39 $y^{3} (50 y^{2} - 98) \div 26 y^{2} (5 y + 7)$

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Solution

$50 y^{2} - 98 = 2 (25 y^{2} - 49) = 2 ((5 y)^{2} - (7)^{2}) = 2 (5 y + 7) (5 y - 7)$
$39 y^{3} (50 y^{2} - 98) \div 26 y^{2} (5 y + 7) = \frac{39 y^{3} (50 y^{2} - 98)}{26 y^{2} (5 y + 7)} = \frac{78 y^{3} (5 y - 7) (5 y + 7)}{26 y^{2} (5 y + 7)} = 3 y (5 y - 7)$

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39 y^{3} (50 y^{2} - 98) \div 26 y^{2} (5 y + 7)

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39 y^{3} (50 y^{2} - 98) \div 26 y^{2} (5 y + 7)

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Factorise the expressions and divide them as directed

39 y^{3} (50 y^{2} - 98) \div 26 y^{2} (5 y + 7)

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