Divided $(32 x^{4} y^{3} - 16 x^{3} y^{4})$ by $(- 8 x^{2} y)$

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Solution

$\frac{32 x^{4} y^{3} - 16 x^{3} y^{4}}{- 8 x^{2} y}$

Taking $16 x^{3} y^{3}$ common from numerator,

$\Rightarrow \frac{16 x^{3} y^{3} (2 x - y)}{- 8 x^{2} y}$

$\Rightarrow$ $2 x y^{2} (y - 2 x)$
$\Rightarrow 2 x y^{3} - 4 x^{2} y^{2}$

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