Question

Divided: $9x^{2}y-6xy+12x{y}^{2}by\frac{-3}{2}xy$.

Answer 1

$\frac{9x^{2}y-6xy+12x{y}^2}{-\frac{3}{1}xy}$

$\frac{9x^{2}y}{-\frac{3}{2}xy}-\frac{6xy}{-\frac{3}{2}xy}+\frac{+12xy}{-\frac{3}{2}xy}$

$-6x+4-8y$