Question

Divided it:-
$2^{3/8}by{4}^{7/9}$

Answer 1

Consider the following question.

$\frac{{\left(2\right)}^{\frac{3}{8}}}{{\left(4\right)}^{\frac{7}{9}}}$

$=\frac{{\left(2\right)}^{\frac{3}{8}}}{{\left({\left(2\right)}^2\right)}^{\frac{7}{9}}}=\frac{{\left(2\right)}^{\frac{3}{8}}}{{\left(2\right)}^{\frac{14}{9}}}$

$={\left(2\right)}^{\frac{-85}{72}}$

Hence, this is the required answer.