Dividing 2 x 2 yz 5 by 8 x 2 z 3 gives 1-4 xyz 2A- TrueB- False

The correct option is B False 2x^2yz^5 by 8x^2z^3 can be solved as 2/8= 1/4 x^2/x^2 = 1 y/1 = y z^5/z^3 = z^2 Therefore, 2x^2yz^5/8x^2z^3 = 1/4yz^2, whic ...

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Byju's Answer

Standard IX

Mathematics

Harmonic Mean

Dividing 2 x ...

Question

Dividing $2 x^{2}$ $y$ $z^{5}$ by $8 x^{2}$ $z^{3}$ gives $\frac{1}{4} x y z^{2}$ .

True

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False

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Solution

The correct option is B
False

$2 x^{2}$ $y$ $z^{5}$ by $8 x^{2}$ $z^{3}$ can be solved as -

$\frac{2}{8}$ = $\frac{1}{4}$

$\frac{x^{2}}{x^{2}}$ = $1$
$\frac{y}{1}$ = $y$
$\frac{z^{5}}{z^{3}}$ = $z^{2}$

Therefore, $\frac{2 x^{2} y z^{5}}{8 x^{2} z^{3}} = \frac{1}{4} y z^{2}$ , which is different from $\frac{1}{4} x y z^{2}$ .

Hence the statement is false.

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Division of $72 x^{2}$ $y^{4}$ $z^{6}$ by $8 x^{2}$ $y^{2}$ $z^{3}$ gives $9 y^{2}$ $z^{3}$

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Division of $72 x^{2}$ $y^{4}$ $z^{6}$ by $8 x^{2}$ $y^{2}$ $z^{3}$ gives $9 y^{2}$ $z^{3}$ .

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Dividing 2x2yz5 by 8x2z3 gives 14xyz2.

The correct option is B False 2x2yz5 by 8x2z3 can be solved as - 28= 14 x2x2 = 1 y1 = y z5z3 = z2 Therefore, 2x2yz58x2z3=14yz2, which is different from 14xyz2. Hence the statement is false.

Dividing $2 x^{2}$ $y$ $z^{5}$ by $8 x^{2}$ $z^{3}$ gives $\frac{1}{4} x y z^{2}$ .