Question

Dividing $2x^2$$y$$z^5$ by $8x^2$$z^3$ gives $\frac{1}{4}xy{z}^2$.

• A. True
• B. False

Answer 1

The correct option is B

False

$2x^2$$y$$z^5$ by $8x^2$$z^3$ can be solved as -

$\frac{2}{8}$= $\frac{1}{4}$

$\frac{x^2}{x^2}$ = $1$
$\frac{y}{1}$ = $y$
$\frac{z^5}{z^3}$ = $z^2$

Therefore, $\frac{2x^{2}y{z}^5}{8x^2{z}^3}=\frac{1}{4}y{z}^2$, which is different from $\frac{1}{4}xy{z}^2$.

Hence the statement is false.