Dividing a-b2-a-b2 by a2-b2 gives-A- 1B- 2a-bC- 2D- atb

The correct option is C 2 (a+b)^2+(a b)^2 = (a^2 + b^2 + 2ab) + (a^2 + b^2 2ab) = 2(a^2 + b^2 ) (a + b)^2 + (a b)^2/a^2 + b^2 = 2 ...

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Factorisation by Common Factors

Dividing a+b2...

Question

Dividing $(a + b)^{2} + (a - b)^{2}$ by $a^{2} + b^{2}$ gives:

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a+b

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2(a+b)

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Solution

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Similar questions

Dividing $(a + b)^{2} + (a - b)^{2}$ by $(a^{2} + b^{2})$ gives ___

The following facts are available :

2 A^{⊖} + B_{2} \to 2 B^{⊖} + A_{2}

2 C^{⊖} + B_{2} \to N o r e a c t i o n

2 D^{⊖} + A_{2} \to 2 A^{⊖} + D_{2}

a, b

c

\frac{a}{c} =

(2 a + b)^{2}

Factorising and dividing $a^{2} + 7 a + 10$ by (a + 5) gives:

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