Dividing $(x^{2}) + 3) (x^{2} - 3) + 9$ by $x^{4}$ gives

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Solution

The correct option is D 1

$\frac{(x^{2} + 3) (x^{2} - 3) + 9}{x^{4}}$

$= \frac{x^{4} - 9 + 9}{x^{4}}$

$= 1$

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Similar questions

Divide ( $x^{2}$ +3)( $x^{2}$ -3)+9 by $x^{4}$

x^{4} + 3 x^{2} - 10

x^{2} + 5

p (x) = x^{4} - 3 x^{2} + 4 x + 5

g (x) = x^{2} + 1 - x

Divide the polynomial p(x) by the polynomial g(x) and find the quotient and remainder in each of the following:

(i)

(ii)

(iii)

p (x) = x^{4} - 3 x^{2} + 4 x + 5

g (x) = x^{2} + 1 - x

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