Question

$DL$ and $BM$ are the heights on sides $AB$ and $AD$ respectively of parallelogram ABCD. If the area of the parallelogram is $1470{cm}^2$, $AB=35cm$ and $AD=49cm$, find the length of $BM$ and $DL$

Answer 1

Given: Area of parallelogram $=1470c{m}^2$
$AB=35cm$ and $AD=49cm$

We know that, area of parallelogram $=base\times height$

On substituting the values we get

$\Rightarrow$ $1470=35\times DL$ [When base is $AB,$ height is $DL$]

$\Rightarrow$ $DL=\frac{1470}{35}$

$\Rightarrow DL=42cm$

Again, Area of parallelogram $=base\times height$

$\Rightarrow$ $1470=49\times BM$ [When $AD$ is the base, $BM$ is the height]

$\Rightarrow$ $BM=\frac{1470}{49}$

$\Rightarrow BM=30cm$

Thus, the lengths of $DL$ and $BM$ are $42cm$ and $30cm$ respectively.