Question

Do the following activity -
Activity I : Total number of students in your class, n(S) = $\boxed{x}$

Number of students from your class, wearing spectacles, n(A) = $\boxed{x}$

Probability of a randomly selected student wearing spectacles, P(A) = $\boxed{x}$

Probability of a randomly selected student not wearing spectacles, P(B) = $\boxed{x}$

Activity II : Decide the sample space yourself and fill in the following boxes.

Answer 1

Activity I :

Total number of students in your class, n(S) = 40

Number of students from your class, wearing spectacles, n(A) = 6

Probability of a randomly selected student wearing spectacles, P(A) = $\frac{6}{40}$
$=\frac{3}{20}$

Probability of a randomly selected student not wearing spectacles, P(B) = $\frac{40-6}{40}$
$$\begin{gathered} =\frac{34}{40} \\ =\frac{17}{20} \end{gathered}$$

Activity II :
Let us suppose the sample space be {1, 2, 3, 4, 5, 6, 7, 8, 9 10}
Event A: Getting an even number
A = {2, 4, 6, 8, 10}
∴ n(A) = 5
Now, $\mathrm{P}\left(\mathrm{A}\right)=\frac{\mathrm{n}\left(\mathrm{A}\right)}{\mathrm{n}\left(\mathrm{S}\right)}$

$$\begin{gathered} =\frac{5}{10} \\ =\frac{1}{2} \end{gathered}$$