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Question

Do the following subtractions as directed.
Subtract t4−3t2+7 from 5t3−9

A
t43t25t3+16
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B
t45t33t2+16
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C
t4+5t3+3t216
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D
t45t33t216
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Solution

The correct option is C t4+5t3+3t216
We know that Like terms are terms that contain the same variables raised to the same power.

The only like term in the given expressions t43t2+7 and 5t39 are 7 and 9. So we group together the like terms and subtract t43t2+7 from 5t39 as follows:

(5t39)(t43t2+7)=5t39t4+3t27=t4+5t3+3t2+(97)=t4+5t3+3t216

Hence, (5t39)(t43t2+7)=t4+5t3+3t216.

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