Do you want to have an idea of how small a nucleus is- Let-s try finding the nuclear radius of 125-60 X The value of R 0 is 1-1 - 10-15 SI units- R - 10-15 m

R=R_0A^1/3 where A is the mass number. Here the element that is given is nbsp; ^125_60X So its mass number is 125. R=R_0 × 125^1/3 R=1.1 × 10^ 15× 5 m=5.5 × ...

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Standard XII

Chemistry

Parameters of Nucleus

Do you want t...

Question

Do you want to have an idea of how small a nucleus is? Let's try finding the nuclear radius of $_{60}^{125} X$ . (The value of $R_{0} i s 1.1 \times 10^{- 15} S I$ units.) R= $\times 10^{- 15} m$

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Solution

$R = R_{0} A^{\frac{1}{3}}$ where A is the mass number.
Here the element that is given is $_{60}^{125} X$
So its mass number is 125.
$R = R_{0} \times 125^{\frac{1}{3}} R = 1.1 \times 10^{- 15} \times 5 m = 5.5 \times 10^{- 15} m$

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Do you want to have an idea of how small a nucleus is? Let's try finding the nuclear radius of $_{60}^{125} X .$

The value of $R_{0} i s 1.1 \times 10^{- 15} S I$ units.

Ans:___ $X 10^{- 15} m$

Do you want to have an idea of how small a nucleus is? Let's try finding the nuclear radius of $_{60}^{125} X .$

The value of $R_{0} i s 1.1 \times 10^{- 15} S I$ units.

Ans:___ $X 10^{- 15} m$

Q. Do you want to have an idea of how small a nucleus is? Let's try finding the nuclear radius of

_{60}^{125} X

. (The value of

R_{0} i s 1.1 \times 10^{- 15} S I

units.) R=

\times 10^{- 15} m

Q. Find the radius of nucleus of an atom having atomic mass number equal to 125.

(T a k e R_{0} = 1.3 \times 10^{- 15} m)

Q. The radius of

_{29} {C u}^{64}

nucleus in Fermi is (given

R_{0} = 1.2 \times 10^{- 15} m

)

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Do you want to have an idea of how small a nucleus is? Let's try finding the nuclear radius of 12560X. (The value of R0 is 1.1×10−15 SI units.) R= ×10−15m

R=R0A13 where A is the mass number. Here the element that is given is 12560X So its mass number is 125. R=R0×12513R=1.1×10−15×5m=5.5×10−15m

Do you want to have an idea of how small a nucleus is? Let's try finding the nuclear radius of $_{60}^{125} X$ . (The value of $R_{0} i s 1.1 \times 10^{- 15} S I$ units.) R= $\times 10^{- 15} m$

$R = R_{0} A^{\frac{1}{3}}$ where A is the mass number.
Here the element that is given is $_{60}^{125} X$
So its mass number is 125.
$R = R_{0} \times 125^{\frac{1}{3}} R = 1.1 \times 10^{- 15} \times 5 m = 5.5 \times 10^{- 15} m$