Aluminium will burn in oxygen with a brilliant white flame to form the trioxide alumnium(III) oxide, Al2O3.
4Al(s) + 3O2(l) → 2Al2O3(s)
Aluminium metal reacts vigorously with all the halogens to form aluminium halides. So, it reacts with chlorine, Cl2, bromine, I2, and iodine, I2, to form respectively aluminium(III) chloride, AlCl3, aluminium(III) bromide, AlBr3, and aluminium(III) iodide, AlI3.
2Al(s) + 3Cl2(l) → 2AlCl3(s)
2Al(s) + 3Br2(l) → Al2Br6(s)
2Al(s) + 3I2(l) → Al2I6(s)