Question

Does liquid pressure at a point depends on the shape and size of the container?

Answer 1

Dear Student,

$$\begin{gathered} \mathrm{Pressure}\mathrm{exerted}\mathrm{by}\mathrm{the}\mathrm{liquid}\mathrm{at}\mathrm{the}\mathrm{depth}\mathrm{is}, \\ \mathrm{P}=\mathrm{h\rho g} \\ \mathrm{where},\mathrm{h}=\mathrm{height}\mathrm{of}\mathrm{liquid}\mathrm{column} \\ \mathrm{\rho }=\mathrm{density}\mathrm{of}\mathrm{liquid} \\ \mathrm{g}=\mathrm{acceleration}\mathrm{due}\mathrm{to}\mathrm{gravity} \\ \mathrm{which}\mathrm{means}\mathrm{it}\mathrm{is}\mathrm{independent}\mathrm{of}\mathrm{the}\mathrm{shape}\mathrm{and}\mathrm{size}\mathrm{of}\mathrm{the}\mathrm{container}. \end{gathered}$$

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