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Question

Does the number of moles of reaction products increase, decrease or remain same when each of the following equiibria is subjected to a decrease in pressure bp increasing the volume?
i) PCl5PCl3(g)+Cl2(g)
ii) CaO(s)+CO2(g)CaCO3(s)
iii) 3Fe(s)+4H2O(g)Fe3O4(s)+4H2(g)

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Solution

According to Le Chatelier’s principle, if the pressure on the system is decreased, then the equilibrium shifts in the direction in which the number of moles of gases is more.

i)
The number of moles of reaction products will increase. In the given reaction,

PCl5(g)PCl3(g)+Cl2(g)

The number of moles of gaseous products is more than that of gaseous reactants. Thus, the reaction will proceed in the forward reaction. As a result, the number of moles of reaction products will increase.

ii) The number of moles of reaction products will decrease. In the given reaction,

CaO(s)+CO2(g)CaCO3(s)

The number of moles of gaseous products is less than that of gaseous reactants. Thus, the reaction will proceed in the backward reaction. As a result, the number of moles of reaction products will decrease.

iii) The number of moles of reaction products remains same. In the given reaction,

3Fe(s)+4H2O(g)Fe3O4(s)+4H2(g)

The number of moles of gaseous products equal to gaseous reactants. Thus, the decreasing of pressure does not affect the equilibrium. As a result, the number of moles of reaction products will remain same.


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