Question

Domain = {1, 2, 3}
Range = {7, 5}, It is a function
If $f\left(x\right)=x^3-\frac{1}{x^3}$, then find $f\left(x\right)+f\left(\frac{1}{x}\right)$

Answer 1

$$\begin{gathered} f\left(x\right)=x^3-\frac{1}{x^3} \\ f\left(\frac{1}{x}\right)=\frac{1}{x^3}-x^3 \\ f\left(x\right)+f\left(\frac{1}{x}\right)=\frac{1}{x^3}-x^3+x^3-\frac{1}{x^3}=0 \end{gathered}$$