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Byju's Answer
Standard XII
Mathematics
Standard Formulae - 2
Domain of giv...
Question
Domain of given :
y
=
√
log
{
sin
(
x
3
2
−
1
)
}
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Solution
y
=
√
log
e
{
sin
(
x
2
3
−
1
)
}
y
is defined if
log
e
{
sin
(
x
2
3
−
1
)
}
≥
0
log
e
{
sin
(
x
2
3
−
1
)
}
≥
log
e
1
sin
(
x
2
3
−
1
)
≥
1
x
2
3
−
1
≥
sin
−
1
1
x
2
3
≥
π
2
x
2
≥
3
π
2
+
9
|
x
|
≥
√
3
π
2
+
9
x
≤
−
√
3
π
2
+
9
OR
x
≥
√
3
π
2
+
9
∴
domain
x
ϵ
(
−
∞
,
−
√
3
π
2
+
9
]
∪
[
√
3
π
2
+
9
,
∞
)
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