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Question

Double ordinate AB of the parabola y2=4ax subtends an angle π2 at the vertex of the parabola, then tangents drawn to parabola at A and B will intersect at

A
(4a,0)
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B
(2a,0)
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C
(3a,0)
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D
None of these
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Solution

The correct option is C (4a,0)
Let A(at2,2at),B(at2,2at).
mOA=2t,mOB=2t
Thus, (2t)(2t)=1
t2=4
Equation of tangent through A is
yt=x+at2
Equation of tangent through B is
yt=x+at2
x=at2
x=4a
y=0
Thus, tangents will intersect at (4a,0).

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