Draw a circle of radius 3.5 cm and construct a chord of length 6 cm in it. Measure the distance between the centre and the chord.

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Solution

Draw a circle of radius $r = 3.5 c m$
Mark an arc of $6 c m$ from any point on circle on the circumference.
Let $M$ be the midpoint of chord $A B$
(Line passing through $M$ and center $O$ is the perpendicular bisector of chord $A B$ )
$M B = 3 c m O B = 3.5 c m (O M)^{2} + (M B)^{2} = (O B)^{2} O M = \sqrt{(O B)^{2} - (M B)^{2}} O M = \sqrt{(3.5)^{2} - 3^{2}} O M = 1.8027 c m$

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Draw a circle of radius 3.5 cm and construct a chord of length 6 cm in it. Measure the distance between the centre and the chord.

Draw a circle of radius r=3.5cmMark an arc of 6cm from any point on circle on the circumference.Let M be the midpoint of chord AB(Line passing through M and center O is the perpendicular bisector of chord AB)MB=3cmOB=3.5cm(OM)2+(MB)2=(OB)2OM=√(OB)2−(MB)2OM=√(3.5)2−32OM=1.8027cm