Given: Radius of the circle=3cm, OP=7cm.
Construction:
(i) With O as the centre draw a circle of radius 3cm.
(ii) Mark a point P at a distance of 7cm from O and join OP.
(iii) Draw the perpendicular bisector of OP. Let it meet OP at M.
(iv) With M as centre and MO as radius, draw another circle.
(v) Let the two circles intersect at T and T'.
(vi) Join PT and PT'. They are the required tangents. Length of the tangent, PT=6.3cm.
Verification:
In the right angled Δ OPT,
PT=√OP2−OT2=√72−32
=√49−9=√40
∴PT=6.3cm(approximately).