Draw a circle of radius 6 cm. Construct the two tangents to the circle from a P which is at the distance of 9 cm from centre. Measure the length of the tangents.

4.7 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

6.7 cm

Right on! Give the BNAT exam to get a 100% scholarship for BYJUS courses

7.7 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

5.7 cm

No worries! We‘ve got your back. Try BYJU‘S free classes today!

Open in App

Solution

The correct option is B
6.7 cm

Draw a circle of radius 6 cm and mark its centre as O.

Mark a point P outside the circle such that OP is 9 cm.

Join OP.

Bisect OP at C.

Taking C as centre and OC as the radius draw a circle which intersect the previous circle at T and T’.

Join PT and PT’ which are the required tangents. Measure PT and PT’. It will be equal to 6.7 cm (approx.)

Alternate Method -
Since OT is perpendicular to TP
We can use Pythagoras Theorem, In $△ O T P$
$P T^{2} = 9^{2} - 6^{2}$

PT = $\sqrt{45}$ = 6.7 cm

Suggest Corrections

Similar questions

Mark a point P outside the circle of radius 6 cm with centre O. Construct the two tangents to the circle from P which is at the distance of 9 cm from centre. Measure the length of the tangents.

Draw a circle of radius 3.5 cm. Mark a point P outside the circle at a distance of 6 cm from the centre. Construct two tangents from P to the given circle. Measure and write down the length of one tangent.

Q. Draw a circle of radius 4 cm. Construct the two tangents to the circle from a P which is at the distance of 7 cm from centre. Measure the length of the tangents

Q. Draw a circle with centre O and radius 3.5 cm. Take point P at a distance 5.7 cm from the centre. Draw tangents to the circle from point P.

Q. Draw a circle of radius 6 cm. From a point 10 cm away from its centre, construct the pair of tangents to the circle and measure their lengths.

Join BYJU'S Learning Program