Question

Draw a circle with center at point P. Draw its radii PA and PB such that angle APB= ${90}^0$. Shade the minor sector of the circle by horizontal lines and its major sector by vertical lines.

Answer 1

A circle with centre P and any radius r is drawn.

At P we draw $\angle APB={90}^o$.

PB meets the circumference at B.

$ar.(sectorwithcentralangle\angle APB={90}^o)$ is

$\frac{{90}^o}{{360}^o}\pi r^2=\frac{1}{4}\pi r^2$.

$ar.(sectorwithcentralangle\angle APB={360}^o-{90}^o={270}^o)$ is $\frac{{270}^o}{{360}^o}\pi r^2=\frac{3}{4}\pi r^2$.

Sector PAB with central angle ${90}^o$ is minor one and sector PAB with central angle ${360}^o-{90}^o={270}^o$ is the major one.