wiz-icon
MyQuestionIcon
MyQuestionIcon
1
You visited us 1 times! Enjoying our articles? Unlock Full Access!
Question

Draw a diagram of combination of three movable pulleys and one fixed pulley to lift up a load. In the diagram, show the directions of load, effort and tensiom in each strand. Find : (i) the mechanical advantage , (ii) the velocity ratio, and (iii) the efficiency of the combination, in the ideal situation.

Open in App
Solution


T e n s i o n space T subscript 1 space i n space t h e space s t r i n g space p a s sin g space o v e r space t h e space p u l l e y space A space i s space g i v e n space a s space 2 T subscript 1 equals L space o r space T subscript 1 equals L over 2 T e n s i o n space T subscript 2 equals i n space t h e space s t r i n g space p a s sin g space o v e r space p u l l e y space B space i s space g i v e n space a s space 2 T subscript 2 equals T subscript 1 space end subscript space o r space o r space T subscript 2 equals T subscript 1 over 2 equals L over 2 squared T e n s i o n space T subscript 3 i n space t h e space s t r i n g space p a s sin g space o v e r space t h e space p u l l e y space C space i s space g v e n space a s 2 T subscript 3 equals T subscript 2 space o r space T subscript 3 equals T subscript 2 over 2 equals L over 2 cubed i n space e q u i l i b r i u m space T subscript 3 equals E E equals L over 2 cubed
(i) Mechanical advantage = MA = L/E = 23

(ii)
As one end of each string passing over a movable pulley is fixed, so the free end of string moves twice the distance moved by the movable pulley.
If load L moves up by a distance x, dL = x, effort moves by a distance 23x, dE = 23x
V e l o c i t y space r a t i o equals fraction numerator D i s tan c e space m o v e d space b y space t h e space e f f o r t space d subscript E over denominator D i s tan c e space m o v e d space b y space t h e space l o a d space d subscript L end fraction equals fraction numerator 2 cubed x over denominator x end fraction equals 2 cubed

(iii)
E f f i c i e n c y b equals fraction numerator M A over denominator V R end fraction equals 2 cubed over 2 cubed equals 1 space space o r space 100 percent sign




flag
Suggest Corrections
thumbs-up
7
Join BYJU'S Learning Program
Join BYJU'S Learning Program
CrossIcon