Draw a diagram to show conservation of mechanical energy in case of free falling body.

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Solution

Initial mechanical energy $= \frac{1}{2} m u^{2} + m g h = m g h$

Final mechanical energy $= \frac{1}{2} m v^{2}$
Since mechanical energy is conserved,
$m g h = \frac{1}{2} m v^{2}$

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Draw a diagram to show conservation of mechanical energy in case of free falling body.

Initial mechanical energy=12mu2+mgh=mghFinal mechanical energy =12mv2Since mechanical energy is conserved,mgh=12mv2

Initial mechanical energy $= \frac{1}{2} m u^{2} + m g h = m g h$

Final mechanical energy $= \frac{1}{2} m v^{2}$
Since mechanical energy is conserved,
$m g h = \frac{1}{2} m v^{2}$