Draw a graph and represent the zeroes of the quadratic polynomial for the equation $y = x^{2} + 5 x + 6$ .

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Solution

Factor of $x^{2} + 5 x + 6 = (x + 2) (x + 3)$
Plotting $(- 1, 2) (- 2, 0) (- 3, 0) (- 4, 2$ ) and joining them.
Here, the graph cuts x-axis at two distinct points $A$ and $A^{'}$ .
The $x$ -coordinates of $A (- 2, 0)$ and $A^{'} (- 3, 0)$ are the two zeroes of the quadratic polynomial $y = x^{2} + 5 x + 6$ .

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