Draw a graph showing the variation of stopping potential $(V_{0})$ with the $3$ frequency of incident radiation $(v)$ in relation to the electric effect.
How can the value of Plancks constant be determined from this graph?

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Solution

Slope of the graph corresponds to $\frac{h}{e}$ which is a
constant and independent of the material.

so tan $ϕ$ = $\frac{h}{e}$

therefore

h = $\frac{e}{t a n ϕ}$

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Similar questions

Q. Following graphs show the variation of stopping potential corresponding to the frequency of incident radiation (F) for a given metal. The correct variation is shown in graph (

v_{0}

= Threshold frequency) :

Q. The graph shows variation of stopping potential

V_{0}

versus frequency of incident radiation

v

for two photosensitive metals A and B. Which of the two metals has higher threshold frequency and why?

Derive the expression for the stopping potential in terms of frequency of incident radiation and hence draw the graph showing the variation of the two quantities with respect to each other.

Q. The graph shows variation of stopping potential

V_{0}

versus frequency of incident radiation for two photosensitive metals A and B. Which of the two metals has higher threshold frequency and why?

Q. Plot a labelled graph of

| V_{s} |

where

V_{s}

is stopping potential versus frequency f of the incident radiation.
State how will you use this graph to determine the value of Planck's constant.

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Draw a graph showing the variation of stopping potential (V0) with the 3 frequency of incident radiation (v) in relation to the electric effect.How can the value of Plancks constant be determined from this graph?

Slope of the graph corresponds to he which is a constant and independent of the material.so tan ϕ = hetherefore h = etanϕ

Draw a graph showing the variation of stopping potential $(V_{0})$ with the $3$ frequency of incident radiation $(v)$ in relation to the electric effect.
How can the value of Plancks constant be determined from this graph?

Slope of the graph corresponds to $\frac{h}{e}$ which is a
constant and independent of the material.

so tan $ϕ$ = $\frac{h}{e}$

therefore

h = $\frac{e}{t a n ϕ}$