Draw a graph to show a variation of resistance of a metal wire as a function of its diameter keeping its length and material constant.

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Solution

$R = p \frac{1}{A} \Rightarrow \frac{1}{π r^{2}} = p \frac{4 l}{π D^{2}}$
i.e. $R α \frac{1}{A} \Rightarrow$ R is inversely proportional to diameter.

Hence, graph of resistance (R) versus diameter (D) is of the following form.

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Draw a graph to show a variation of resistance of a metal wire as a function of its diameter keeping its length and material constant.

R=p1A⇒1πr2=p4lπD2i.e. Rα1A⇒ R is inversely proportional to diameter.Hence, graph of resistance (R) versus diameter (D) is of the following form.

$R = p \frac{1}{A} \Rightarrow \frac{1}{π r^{2}} = p \frac{4 l}{π D^{2}}$
i.e. $R α \frac{1}{A} \Rightarrow$ R is inversely proportional to diameter.

Hence, graph of resistance (R) versus diameter (D) is of the following form.