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Question

Draw a histogram for the adjacent data.
Class interval091014152425293034
Frequency6412108

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Solution

Observe that the class intervals are given in inclusive form. We have to convert these into exclusive form by applying the correction factor. The correction factor is 0.5. This is subtracted from the lower limit and added to the upper limit. First let us prepare a table of the required data for drawing the histogram as below:
Actual Class interval)0.59.59.514.51414.524.524.529.529.534.5
Frequency6412108
Class width1051055
Length of the rectangle =(fwidth×C)610×5=345×5=41210×5=6105×5=1085×5=8
Taking the scale on X-axis as 1 cm=5 and Y-axis as 1 cm=1, we can draw the histogram. The histogram looks as:
610594_559924_ans.jpg

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