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Question

Draw a histogram for the following data:

Marks1015152020252530304040606080Number of candidates798512128

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Solution

We have,

Marks1015152020252530304040606080Number of candidates798512128

As, in the above given table the classes are of unequal widths, so let us form the table with adjusted frequencies where adjusted frequencies can be found as followed:

Adjusted frequency =Chosen class widthActual Class width×Actual Frequency

Marks1015152020252530304040606080Number of candidates798512128Adjusted Frequency55×7=755×9=955×8=855×5=5510×12=6510×12=3520×8=2

Now, the histogram for the given data is as follows where kink represents the unequal class intervals.


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