Draw a histogram for the following data:
Marks10−1515−2020−2525−3030−4040−6060−80Number of candidates798512128
We have,
Marks10−1515−2020−2525−3030−4040−6060−80Number of candidates798512128
As, in the above given table the classes are of unequal widths, so let us form the table with adjusted frequencies where adjusted frequencies can be found as followed:
Adjusted frequency =Chosen class widthActual Class width×Actual Frequency
Marks10−1515−2020−2525−3030−4040−6060−80Number of candidates798512128Adjusted Frequency55×7=755×9=955×8=855×5=5510×12=6510×12=3520×8=2
Now, the histogram for the given data is as follows where kink represents the unequal class intervals.