Draw a labeled ray diagram to show the path of a ray of light incident obliquely on one face of a glass slab.

Open in App

Solution

The angle of incidence is equal to the angle of emergence for a light ray incident obliquely on a glass slab ie $i = e$
Hence the emergent ray is parallel to the incident ray
Given below is a systematic diagram for the path of a light incident obliquely on a glass slab.

Suggest Corrections

Similar questions

(a) With the help of a diagram, show how when light falls obliquely on the side of a rectangular glass slab, the emergent ray is parallel to the incident ray. . (b) Show the lateral displacement of the ray on the diagram. (c) State two factors on which the lateral displacement of the emergent ray depends.

Q. A ray of light travelling in air is incident on a rectangular glass block and emerges out into the air from the opposite face. Draw a labelled ray diagram to show the completer path of this ray of light. Mark the two points where the refraction of light takes place. What can you say about the final direction of ray of light?

Q. Draw a ray diagram to illustrate how a ray of light incident obliquely on one face of a rectangular glass slab of uniform thickness emerges.

Q. Trace the path of the ray of light through a glass slab, when it passes from water to a glass slab and what will happen to the incident ray ? Draw the ray diagram.

Q. WHEN A RAY OF LIGHT TRAVELLING IN AIR ENTERS OBLIQUELY INTO A GLASS SLAB,IT IS OBSERVED THAT THE LIGHT RAY EMERGES PARALLEL TO THE INCIDENT RAY BUT IT IS SHIFTED SIDEWAYS SLIGHTLY.DRAW A RAY DIAGRAM TO ILLUSTRATE IT

Join BYJU'S Learning Program

Draw a labeled ray diagram to show the path of a ray of light incident obliquely on one face of a glass slab.

The angle of incidence is equal to the angle of emergence for a light ray incident obliquely on a glass slab ie i=eHence the emergent ray is parallel to the incident rayGiven below is a systematic diagram for the path of a light incident obliquely on a glass slab.

The angle of incidence is equal to the angle of emergence for a light ray incident obliquely on a glass slab ie $i = e$
Hence the emergent ray is parallel to the incident ray
Given below is a systematic diagram for the path of a light incident obliquely on a glass slab.