Draw a line AB=6 cm. Draw the locus of all the points which are equidistant from A and B.

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Solution

Steps of construction:-
(i) Draw a line segment $A$ of $6 m$ .
(ii) Draw perpendicular bisector $L M$ of $A B . L M$ is the required locus.
(iii) Take any point on $L M$ say $O$ .
(iv) Join $O A$ and $O B$ . Since $O$ lies on the right bisector of the line $A B$
Therefore, $O$ is equidistant from $A$ and $B$ , i.e.,
$O A = O B$
Hence perpendicular bisector of $A B$ is the locus of all the points which are equidistant from $A$ and $B$ .

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