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Question

Draw a line AB and take two points C and E on opposite sides of AB. Through C, draw CD ⊥ AB and through E draw EF ⊥ AB. (Using (i) ruler and set-squares (ii) ruler and compassed)

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Solution

(i) Draw a line AB and take two points C and E on the opposite sides of the line AB.
On the side of E, place a set-square PQR, such that its one arm PQ of the right angle is along the line AB.
Without disturbing the position of the set-square, place a ruler along its edge PR.
Now, without disturbing the position of the ruler, slide the set square along the ruler until the arm QR reaches point C.
Without disturbing the position of the set-square, draw a line CD, where D is a point on AB.
CD is the required line and CD ⊥ AB. We repeat the same process starting with taking set-square on the side of E, we draw a line EF ⊥ AB.










(ii) Draw a line AB and take two points C and E on its opposite sides.
With C as centre, draw an arc PQ, which intersects line AB at P and Q.
Taking P and Q as centres, construct two arcs, such that they intersect each other at H.
Join points H and C.
HC crosses AB at D.
We have CD ⊥ AB.

Similarly, take E as centre and draw an arc RS.
Taking R and S as centres, draw two arcs which intersect each other at G.
Join points G and E.
GE crosses AB at F.
We have EF ⊥ AB.


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