Question

Draw a line segment AB = 5.5 cm. Mark a point P, such that PA = 6 cm and PB = 4.8 cm. From the point P, draw perpendicular to AB.

Answer 1

Step of Construction :

1. Draw a line segment AB = 5.5 cm

2. With A as centre and radius = 6 cm, draw an arc.

3. With B as centre and radius = 4.8 cm draw another arc.

4. Let these arcs meet each other at the point P. $\therefore$ PA = 6 cm, PB = 4.8

5. With P as centre and some suitable radius draw an arc meeting AB at the points C and D.

6. With C as centre and radius more than half of CD, draw an arc.

7. With D as centre and same radius as in step 6, draw an arc.

8. Let these arcs meet each other at the point Q.

9. Join PQ.

10. The PQ meet AB at point O.

Then PO $\perp$ AB i.e. $\angle \text{AOP}={90}^{\circ }=\angle \text{POB}$