Draw a line segment $A B = 7$ cm. Take a point $P$ on $A B$ such that $A P : P B = 3 : 4$ .

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Solution

Steps of construction are as follows:
(1) Draw a line segment AB=7cm
(2)Mark (3+4)=7 points $A_{1}, A_{2}, A_{3}, A_{4}, A_{5}, A_{6}, A_{7}$
(2) Join $A_{7}$ to B
(3) From $A_{3},$ draw $A_{3}$ parallel to $A_{7} B$ meeting AB at P.
(4) Then P is the point on AB in the ratio 3:4

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Draw a line segment AB = 6.2 cm. Mark a point P in AB such that BP= 4 cm. Through point P draw perpendicular to AB.

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7 c m

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\frac{A P}{A B} = \frac{3}{5}

\frac{AP}{AB} = \frac{3}{5}

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