Question

Draw a line segment $AB$ of $8cm$ and bisect it accordingly to obtain:
length $\frac{3}{4}$ of $AB$

Answer 1

We have

$AB=8cm$

So, $\frac{3}{4}AB=\frac{3}{4}\times 8=6cm$

Now, Step of construction

$1.$ Draw a line segment $AB=8cm$

$2.$ Bisect the line segment AB using compass and name the points as $O$.

$3.$ Now, bisects the line segment AO using compass and name the point as $F$.

$4$ $FB$ is the required line that is $\frac{3}{4}ofAB$

As, $OF=1/4ofAB$ as it is half of $AO$ and $OB=1/2ofAB$

So,

$FB=OF+OB$

$\frac{1}{4}-\frac{1}{2}=\frac{3}{4}$

$\therefore FB=\frac{3}{4}AB=6cm$