Draw a line segment AB of length 8 cm and name its midpoint as M. Find the point which is 5 cm away from point B and equidistant from A and B. Name this point to be P. Then the length of PM is

2 cm

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3 cm

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4 cm

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5 cm

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Solution

The correct option is B
3 cm

Steps of construction:

Draw a line segment AB of length 8 cm. Name its midpoint as M.

Draw the perpendicular bisector of AB.

(We know that the locus of a point which is equidistant from two fixed points is the perpendicular bisector of the line segment joining the fixed points. So, in order to find a point which is equidistant from A and B, we draw a perpendicular bisector of AB).

With B as the centre, draw a circle of radius 5 cm.

(This gives us a point which is 5 cm away from B).

Name the point of intersection of the circle and the perpendicular bisector of AB as P.

Then P is the required point.

On measuring, length of PM is 3 cm.

Suggest Corrections

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