Question

Question 89

Draw a line segment of length 10 cm. Divide it into four equal parts. Measure each of these parts.

Answer 1

A perpendicular bisector of a line segment is a line segment perpendicular to and passing through the midpoint of

Steps of construction are as follows:

Step I: Firstly, draw a line segment $\overline{AB}=10cm$

Step II: With A and B as centre and the radius more than half of AB cut an arc both on sides of AB at R and S. Join RS, it is the perpendicular bisector of AB, i.e. AO = OB

Step III: Now, with A and O as centre and the radius more than half of AO, cut an arc on both sides of AO at T and U. Join TU, it is the perpendicular bisector of AO, i.e. AP = PO

Step IV: Again, with O and B as centre and the radius more than half of OB, cut an arc on both sides of OB at X and Y. Join XY, it is the perpendicular bisector of OB, i. e. OQ = QB

Step V: The line segment $\overline{AB}$ is divided into 4 equal parts; such that AP, PO, OQ, and QB.

Step VI: By actual measurement, we have $\overline{AP}=\overline{PO}=\overline{OQ}=\overline{QB}=2.5cm$