Draw a line segment of length $7.6$ cm and divide it in the ratio $5 : 8$ . Measure the two parts.

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Solution

$D i v i d e a l i n e s e g m e n t o f$ $7.6 c m,$ $l e n g t h i n t h e r a t i o$ $5 : 8$
$a n d m e a s u r e$ .
$m : n = 5 : 8$
$m + n = 5 + 8 = 13$
$A C : C B = 5 : 8$
$b y m e a s u r e m e n t$ $: A C = 3 c m, C B = 4.6 c m$ .
$S t e p s o f c o n s t r u c t i o n$ :
$1. D r a w a n y r a y$ $A B$ , $s u c h t h a t$ $A B = 7.6 c m$
$2. D r a w$ $A$ $X$ $r a y a t p o i n t$ $A$ $m a k i n g a c u t e a n g l e$ .
$3$ . $L o c a t e t h e p o i n t s$ $A_{1}, A_{2}, A_{3}, . . . . . . . . A_{13}$ $f r o m$ $A$ .
$4$ . $J o i n$ $B A_{13}$ . $D r a w$ $B A_{13} | | A_{5} C$ .
$N o w$ , $A C : C B = 5 : 8$
$I f m e a s u r e d$ , $A C = 3 c m, C B = 4.6 c m$ .

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