1. Draw a line segment QR=5 cm.
2. Construct an angle of 90∘ at Q and let this line through Q is QX.
3.Similar way, with R as Centre, construct an angle of 90∘ and let this line through R is RY.
Yes, the line QX and YR are parallel.
Since, ∠XQR=∠YRP (corresponding angles)