Question

Draw a line segment $XY=7cm$ and draw $\angle AXY={90}^{\circ }$

Answer 1

$1.$Draw a line $XY=7$cm. Taking $X$ as center, and radius more than $\frac{1}{2}XY$,draw arcs on top and bottom of $XY$

$2.$Taking $X$ as center, and radius as before,draw arcs on top and bottom of $XY$

$3.$Let the point where arcs intersect on top of $XY$ be $P$.And the point where arcs intersect at the bottom be $Q$.Join $PQ$

$4.$Let $PQ$ intersect $XY$ at the point $M$.

Thus, line $PMQ$ is the required perpendicular bisector of $XY$.