Question

Draw a quadrilateral in the cartesian plane, whose vertices are (-4, 5), (0, 7), (5, -5) and (-4, -2). Also find its area.

Answer 1

Area of quadrilateral ABCD = area of $\Delta BCE$ + area of trap. ABED

$=\frac{1}{2}\times 10.4\times 5+\frac{1}{2}(10.4+7)\times 4$

$=5.2\times 5+2\times 17.4$

= 26 + 34.8 = 60.8 sq. units.