Question

Draw a rough sketch of a hexagon $ABCDEF$. How many diago

does it have? Draw them. How many of them pass through $D$? Write them.

Answer 1

Number of diagonals in a polygon$=\frac{n(n-3)}{2}$, where $n$ is the number of sides of the polygon

Since a hexagon has $6$ sides. Therefore, the Number of diagonals in the hexagon $ABCDEF$ $=\frac{6(6-3)}{2}=\frac{6\times 3}{2}=\frac{18}{2}=9$

$DB,DA$and $DF$ are three diagonals pass through $D$ in the hexagon$ABCDEF$.