Draw a rough sketch of the curve y=√x−1 in the interval [1, 5]. Find the area under the curve and batween the lines x = 1 and x = 5.
Given equation of the curve is y=√x−1
⇒y2=x−1
∴ Area of shaded region, A=∫51(x−1)12dx=[2.(x−1)323]51=[23.(5−1)32−0]=163sq units