Draw a trapezium ABCD in which AB||DC, AB=7 cm, BC=5 cm, AD=6.5 cm and angle B =60°.

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Solution

Steps of Construction:
1) Draw a line segment AB = 7 cm
2) With B as the centre, draw a ray BX such that ∠ABX = 60°.
3) Again with B as centre and radius BC = 5 cm draw an arc on ray BX. Mark the intersection point as C
4) With C as the centre, draw a ray CY such that ∠BCY = 120°
5) Next with A as centre and radius, AD = 6.5 cm draw an arc such that it intersects the ray CY. Mark the intersection point as D.
6) Join A, D.
Thus ABCD is the required trapezium.

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Draw a trapezium ABCD in which AB || DC, AB = 7 cm, BC = 5 cm, AD = 6.5 cm and $∠ B = 60^{\circ}$

In the adjoining figure,ABCD is a trapezium in which AB||DC;AB=7 cm;AD=BC=5 cm and the distance between AB and DC is 4 cm.Find the length of DC and hence,find the area of trap,ABCD.

Construct a quadrliateral ABCD; if:

(i) AB = 4.3 cm, BC = 5.4, CD = 5 cm, DA = 4.8 cm and $∠$ ABC = $75^{\circ}$ .

(ii) AB = 6 cm, CD = 4.5 cm, BC = AD = 5 cm and $∠ BCD = 60^{\circ}$

(iii) AB = 8 cm, BC = 5.4 cm, AD = 6 cm, $∠ A = 60^{\circ}$ and $∠ B = 75^{\circ}$ .

(iv) AB = 5 cm, BC = 6.5 cm, CD = 4.8 cm, $∠ B = 75^{\circ}$ and $∠ C = 120^{\circ}$

(v) AB = 6 cm = AC, BC = 4 cm, CD = 5 cm and AD = 4.5 cm.

(vi) AB = AD = 5 cm, BD = 7 cm and BC = DC = 5.5 cm

Q. ABCD is a trapezium with

A B ∥ C D

A D = B C = 5 c m, A B = 12 c m

and

C D = 7 c m

, find the area of trapezium ABCD.

Q. In the given figure, ABCD is a trapezium in which AB = 7 cm, AD = BC = 5 cm, DC = x cm, and distance between AB and DC is 4 cm. Find the value of x and area of trapezium ABCD.

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