Question

Draw a triangle ABC with BC = 7 cm, ∠B = 45° and ∠C = 60°. Then construct the another triangle, whose sides are $\frac{3}{5}$ times the corresponding sides of △ABC.

Answer 1

Steps of Construction:
Step I: BC = 7 cm is drawn.
Step II: At B, a ray is drawn making an angle of 45° with BC.
Step III: At C, a ray making an angle of 60° with BC is drawn intersecting the previous ray at A.
Step IV: A ray BX is drawn making an acute angle with BC opposite to vertex A.
Step V: Five points B₁, B₂, B₃, B₄ and B₅ at equal distance is marked on BX.
Step VI: B₅C is joined and B₃C' is made parallel to B₅C.
Step VII: C'A' is made parallel CA.
Thus, A'BC' is the required triangle.