Draw a triangle with sides equal to 3 cm, 7 cm and 6.5 cm. Then the circumradius of this triangle measures
Draw a triangle ABC with the given specifications, AB=6.5 cm, AC = 7 cm and BC = 3 cm.
Draw perpendicular bisectors of sides AB and AC, they meet at O. Join OB.
So, O is the centre and OB is the radius of the circumcircle of △ABC.
From the above constructions, we see that the circumradius of △ABC is 3.5 cm.