Draw a triangle with two sides equal to 4 cm and 5 cm and the angle between them is 60∘. Then the circumcentre of this triangle lies inside the triangle.
Draw triangle ABC with the given specifications, AB=4 cm, AC = 5 cm and ∠BAC = 60∘.
Draw perpendicular bisectors of sides AB and AC, they meet at O. Join OB.
So, O is the centre and OB is the radius of circumcircle of △ABC.
From the above constructions, we see that the circumcentre lies inside the triangle.
Hence the given statement is true.